PROGRAM DOWNLOAD LINKS

If you have a USB cord that allows you to connect to your computer, follow the instructions:

1. Find the program link in the list below.
2. Download the *.8xp file that has the program.
3. Once it's downloaded, connect your calculator via USB cord and power it ON.
4. Find the file, right click it and click "Send to my TI Device"
5. After you verify that you've recieved it on your calculator, safely remove your device.

*CHEMISTRY*
-- Chemical Error --
http://bit.ly/f4XZ8I


-- Compositional Percentage --
http://bit.ly/eWdq6a


-- Graham's Law of Effusion --
http://bit.ly/gCCXtA


-- Ideal Gas Law --
http://bit.ly/gKu1I2


-- Mols, Atoms, Grams Conversion --
http://bit.ly/eTN8qs


-- Molality and Molarity --
Coming Soon

-- pH, pOH, and Titration --
Coming Soon

*GEOMETRY*
-- Distance and Midpoint --
http://bit.ly/gcU54H


-- Pythagorean Theorem --
http://bit.ly/gNpKmd


-- Geometric Mean --
http://bit.ly/ggDwEV


-- Trigonomic Law --
http://bit.ly/hLboIa

*GENERAL MATH*
-- Quadratic Equation --
http://bit.ly/eyFkoZ


*PRE-CALC*
-- Vector Angle --
http://bit.ly/hkMCW6


-- Matrix Cross Multiplying --
Coming Soon

-- Probability Theorems --
http://bit.ly/hnIA5R


*PHYSICS*
-- Pressure --
http://bit.ly/hvd2Ck

Pre-Calc: Probability Theorems

Probability. Uses binomial theorem and combination.

--Combinational

e.g. A 4 person team is chosen from people A, B, C, D, E, F, G. 

P(2 of ABCD, one of EF Are on it)

:>N=3;

:>A=4;

:>B=2;

:>C=2;

:>D=1;

:>E=1;

:>F=1;

Probability = .343 or 34.3%

N = The number of Combinations in the top row. Min of 2; Max of 3.

A through F are the numbers near the Cs. They go straight across.

The program sets up the equation like this: 

(_aC_b)(_cC_d)(_eC_f) = (₄C₂)(₂C₁)(₁C₁) = .343 OR 34.3%

 _(a+c+e)C_(b+d+f)             (₇C₄)

--Binomial Theorem

e.g. 5 people each think of an integer between 4 and 7 inclusive.

P(3 think of '6' or '7')

There are four numbers here: 4, 5, 6, 7.

:>N=5;

:>R=3;

:>P=50% or 1/2 or .5

Probability = .3125 or 31.25%

::N=5 because there are five people.

::R=3 because there are three people thinking.

::P=1/2 because you want to find what they pick from 2 out of 4 numbers.

The program will set the equation up like this:

(N nCr R)(P^R)(1-P)^N-R = (₅C₃)(.5³)(1-.5)^5-3 = (₅C₃)(.5³)(.5)² = .3125 or 31.25%

-- Probability Theorems --

:Menu("METHOD:","BINOMIAL",1,"COMBINATIONAL",2)
:Lbl 1
:Prompt N,R,P
:(N nCr R)(P^R)((1-P)^N-R)→A
:Disp A
:Goto 99
:Lbl 2
:Prompt N
:If N=2:Then
:Prompt A,B,C,D
:A nCr B→X
:C nCr D→Y
:(A+C) nCr (B+D)→Z
:((XY)/Z)→G
:Disp G
:Goto 99
:Else:If N=3:Then
:Prompt A,B,C,D,E,F
:A nCr B→W
:C nCr D→X
:E nCr F→Y
:(A+C+E) nCr (B+D+F)→Z
:((WXY)/Z)→G
:Disp G
:Goto 99:End
:Lbl 99

Chemistry: pH, pOH, and Titration

pOH: the relative concentration of OH ions in a solution.

pH: the relative concentration of H ions in a solution.

Titration: quantitative chemical analysis that is used to determine the unknown concentration of a known reactant.

Use this program to determine the pH or pOH (ambiguous in the program...enter them in the same spot, but remember which one you are using) of a solution given either the concentration of hydroxide or hydrogen for either. It works in reverse too.

>The ":Sci" and ":Normal" commands are in the "MODE" button. Displays in scientific notation of numbers and normal notation of numbers, respectively.

Find:

• pH from pOH
• pH from concentration of OH
• pH from concentration of H
• pOH from pH
• pOH from concentration of OH
• pOH from concentration of H
• concentration of H from pOH
• concentration of H from pH
• concentration of H from concentration of OH
• concentration of OH from pOH
• concentration of OH from pH
• concentration of OH from concentration of H

-- pH --

:Menu("Ion:","Same",9,"Other",10)

:Lbl10

:Menu("Unknown:","Titration",1,"pH or pOH",2)

:Lbl 1

:Menu("Given:","Titration",3,"pH or pOH",4)

:Lbl 3

:Input "Titration: ",A

:((10^-14)/A)→B
:Disp "Titration:",B
:Goto 99
:Lbl 4
:Input "pH or pOH: ",A
:((10^-14)/(10^-A)))→B
:Sci
:Disp "Titration:",B
:Normal
:Goto 99
:Lbl 2
:Menu("Given:","Titration",5,"pH or pOH",6)
:Lbl 5
:Input "Titration: ",A
:(-log(A))→B
:Disp "pH or pOH:",B
:Goto 99
:Lbl 6
:Input "pH or pOH: ",A
:((10^-14)/(10^-A))→B
:(-log(B))→C
:Disp "pH or pOH:",C
:Goto 99
:Lbl 9
:Menu("Unknown:","pH or pOH", 11,"Titration",12)
:Lbl 11
:Input "Titration: ",A
:(-log(A))→B
:Disp "pH:",B
:Goto 99
:Lbl 12
:Input "pH or pOH: ",A
:(10^-A)→B
:Sci
:Disp "Titration:",B
:Normal
:Goto 99
:Lbl 99

Chemistry: Molality and Molarity

The concentration of solutions. If you need this, you know how it works.

--

(grams of solute) = (molality)(molar mass)(Kg solvent)

(grams of solute) = (molarity)(molar mass)(L solvent)

 --

-- Molality --

:Menu("Unknown:","M",1,"Mol.Mass",2,"Kg Solvent",3,"Grams",4)

:Lbl 4

:Input "M: ",M

:Input "Molar Mass: ", G

:Input "Kg Solvent: ",K

:(MGK)→A

:Disp "Grams:",A 

:Goto 99

:Lbl 3

:Prompt G,M

:Input "Mol.Mass",N

:(G)/(MN)→K

:Disp "Kg:",K

:Goto 99

:Lbl 2

:Prompt G,M,K

:(G)/(MK)→N

:Disp "Molar Mass:", N

:Goto 99

:Lbl 1

:Prompt G,K

:Input "Mol.Mass",N

:(G)/(NK)→M

:Disp "M",M

:Goto 99

:Lbl 99

-- Molarity --

:Menu("Unknown:","M",1,"Mol.Mass",2,"L Solvent",3,"Grams",4)

:Lbl 4

:Input "M: ",M

:Input "Molar Mass: ", G

:Input "L Solvent: ",L

:(MGL)→A

:Disp "Grams:",A 

:Goto 99

:Lbl 3

:Prompt G,M

:Input "Mol.Mass",N

:(G)/(MN)→L

:Disp "L:",L

:Goto 99

:Lbl 2

:Prompt G,M,L

:(G)/(ML)→N

:Disp "Molar Mass:", N

:Goto 99

:Lbl 1

:Prompt G,L

:Input "Mol.Mass",N

:(G)/(NL)→M

:Disp "M",M

:Goto 99

:Lbl 99