Wednesday, April 20, 2011

Chemistry: Graham's Law of Effusion

This is straightforward. Finds the mass of a gas during effusion.
e.g. Helium gas effuses 9 times faster than gas X. Find X's molar mass.
: >M = 4; >R = 9;      Unknown mass = 144

-- Graham's Law --
:Input "MOLAR MASS: ",M
:Input "RATE (Porportion): ",R
:(R2(M))A
:Disp "MOLAR MASS:",A

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